中国新声代包威尔:分式的加减

来源:百度文库 编辑:高考问答 时间:2024/03/29 23:37:36
化简
1/[(X+1)(X+2)]+
1/[(X+2)(X+3)]+
1/[(X+3)(X+4)]

原式=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)=1/(x+1)-1/(x+4)=3/[(x+1)(x+4)]