高考问答北京西城区教委:一道计算题 急用
来源：百度文库 编辑：高考问答 时间：2024/05/12 12:25:05
x^2－(x+2)(x-2)－(x+1/x) ^2
=x^2-x^2+4-x^2-2-1/x^2
=-x^2+2-1/x^2
=-(x-1/x)^2
=x^2-x^2+4-x^2-2-1/x^2
=-x^2+2-1/x^2
=-(x-1/x)^2
x^2-x^2+4-x^2-2-1/x^2
=-x^2+2-1/x^2
=-(x-1/x)^2
=x^2-x^2+4-x^2-2-1/x^2
=-x^2+2-1/x^2
=-(x-1/x)^2
x^2－(x+2)(x-2)－(x+1/x) ^2
=x^2-(x^2-4)-[x^2+1/x^2+2x(1/x)]
=x^2-x^2+4-x^2-1/x^2-2
=-x^2-1/x^2+2 or =-(x-1/x)^2