蒙古鹿神最新消息2016:写sql查询语句----高手请进

来源:百度文库 编辑:高考问答 时间:2024/04/20 21:27:08
有3张表,Student表、SC表和Course表
Student表:学号(Sno)、姓名(Sname)、性别(Ssex)、年龄(Sage)和系名(Sdept)
Course表:课程号(Cno)、课程名(Cname)和学分(Ccredit);
SC表:学号(Sno)、课程号(Cno)和成绩(Grade)
请使用SQL语句查询学生姓名及其课程总学分
(注:如果课程不及格,那么此课程学分为0)
现在很多学校执行学分制,只要拿到足够的学分,就能毕业。
学分和成绩的关系:比如《数据库原理》课程,规定有4个学分。只要你这门考试通过,就能拿到4个学分,否则拿不到,这门课程学分为0。
我这里就是要求查询:每个学生总共拿到多少学分
经过测试,回答者的SQL语句都不行,不过给了我灵感,下面是我测试过的正确语句:
方法1:select Sname,sum(Ccredit) as totalCredit from Student,Course,SC where Grade>=60 and Student.Sno=SC.Sno and Course.Cno=SC.Cno group by Sname
方法2:对xyphoenix的修改
select sname,sum(case when sc.grade<60 then 0 else course.Ccredit end) as totalCredit from Student,sc,course where sc.sno=student.sno and sc.cno=course.cno group by sname
方法3:对napolun180410的修改
select Sname,SUM(case when Grade<60 then 0 else Ccredit end) as totalGrade FROM SC JOIN Student ON(Student.sno = SC.sno) JOIN Course ON(SC.Cno = Course.Cno) GROUP BY Student.Sname;
本来想选——无满意答案,但各位热心帮忙,特别是napolun180410,在了解了学分和成绩的关系后,重写了代码,让我挺感动。为此,我改为投票。

if object_id('tempdb..#1') is not null drop table #1
SELECT S.Sno as 'Sno',
S.Sname as 'Sname',
S.Ssex as 'Sse',
S.Sage as 'Sage',
S.Sdept as 'Sdept',
SC.Cno as 'Cno',
SC.Grade as 'Grade',
C.Cname as 'Cname',
'Ccredit' = CASE WHEN SC.Grade >=60 then C.Ccredit ELSE 0 END
INTO #1
FROM Student S
LEFT JOIN SC SC ON SC.Sno = S.Sno
LEFT JOIN COURSE C ON C.Cno = SC.Cno

SELECT SELECT S.Sno as '学号',
S.Sname as '姓名',
S.Ssex as '性别',
S.Sage as '年龄',
S.Sdept as '系名',
SUM(S.Ccredit) as '学分'
FROM #1 S
GROUP BY S.Sno, S.Sname, S.Sex, S.Sage, S.Sdept

drop table #1

我懂了 这样就可以了 你试试

1.先将三张表按照 Sno 和 Cno 的对应关系连接起来
2. 使用CASE语句 当成绩及格(>60) 得到学分 否则为0
3. 按照学号(Sno) 分组.

select Student.Sno,Sname,SUM(case when Grade<60 then 0 else Ccredit end) as totalGrade FROM SC JOIN Student ON(Student.sno = SC.sno) JOIN Course ON(SC.sno = Course.sno) GROUP BY Student.Sno;

select Sname,SUM(case when Grade<60 then 0 else Grade end) as totalGrade FROM Student LEFT JOIN SC ON(Student.sno = SC.sno) GROUP BY Sname;

莫非lz的数据库原理教材也是丁宝康,董健全编写的那本??

select sname,sum(case when sc.grade<60 then 0 else course.credit end) as totalCredit from student,sc,course where sc.sno=student.sno and sc.cno=course.cno and student.sno=123

其中123是学生某个的学号,由于sno是唯一确定一个学生的标识,所以用学号做查询条件。