2017麦王争霸开播时间:问道数学题 要过程的

来源:百度文库 编辑:高考问答 时间:2024/03/29 10:26:20
计算 1/[a(a+1)]+1/[(a+1)(a+2)]+……+1/[(a+2003)(a+2004)]

原式=1/a-1/(a+1)+1/(a+1)-1/(a+2)……+1/(a+2003)-1/(a+2004)
=1/a-1/(a+2004)
=2004/a(a+2004)

1/a(a+1)+.......=1/a-1/(a+1)+1/(a+1)-1/(a+2)+......+1/(a+2003)-1/(a+2004)=1/a-1/(a+2004)=2004/a(a+2004)