网游之邪龙逆天无删txt:x为锐角,且tanx=1/2,求(sin2xcosx-sinx)/(sin2xcos2x)
来源:百度文库 编辑:高考问答 时间:2024/03/29 07:33:52
谢谢
tanx=1/2=>2sinx=cosx
sin^2x+cos^2x=1 x为锐角 sinx=√5/5 cosx=2√5/5
sin2x=2sinxcosx=4/5 cos2x=3/5
(sin2xcosx-sinx)/(sin2xcos2x)
=(4/5*2√5/5-√5/5) /(4/5 *3/5)
=3√5/25
x为锐角,且tanx=1/2,求(sin2xcosx-sinx)/(sin2xcos2x)
已知x^2+p(x+1)+1=0的两根为tanx,tany,且x,y都是锐角,求x+y的值(请写过程)
若x满足sinx<=(1/2)且tanx>=1,则x的取值为多少
1.sin^2(2x)+sin2xcosx-cosx=1 x属于(0,π/2)求sinx tanx的值
求极限1/x^2-1/(tanx)^2 (x趋于无穷大)
已知cos(x+y)=3/5且均为锐角,那siny的值是(请写过程)
sin(TT/4+2x)sin(TT/4-2x)=1/4,求2sin^2x+tanx-cotx-1
已知a,b为锐角,且3(sina)^2+2(sinb)^2=1,3sin2a-2sin2b=0,求a+2b
已知α.β为锐角,且3(sinα)^2+2(sinβ)^2=1,3sin2α-2sin2β=0求α+2β
已知а,в为锐角,且3sin²а+2sin²в=1,3sin2а-2sin2в=0,求а+2в.