热血传奇元宝手机话费:如何解[2+1/(x-1)-1/(x-1)]/[x-x/(1-x*x)]
来源:百度文库 编辑:高考问答 时间:2024/05/21 22:07:45
求救!
对不起...原题应该是:
[2+1/(x-1)-1/(1-x)]/[x-x/(1-x*x)]
对不起...原题应该是:
[2+1/(x-1)-1/(1-x)]/[x-x/(1-x*x)]
=(2-2x^2)/(-x^3)
[2+1/(x-1)-1/(1-x)]/[x-x/(1-x*x)]=2*(1+x)/(x^2)
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如何解[2+1/(x-1)-1/(x-1)]/[x-x/(1-x*x)]
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