猴子种果树阅读:x^2/x-2+4/2-x =？

来源：百度文库 编辑：高考问答 时间：2024/05/10 12:47:27
等于什么要有过程

x^2(x-2)+4/(2-x)
=x^2/(x-2)-4/(x-2)
=(x^2-4)/(x-2)
=(x+2)(x-2)/(x-2)
=x+2
(x不等于2)

x^2/x-2+4/2-x =(x^2/x-x)+(4/2-2)=(x-x)+(2-2)=0
(x不等于0)

没有写清楚吧
应该是x^2/(x-2)+4/(2-x)吧
x^2/(x-2)+4/(2-x)
＝x^2/(x-2)1-/(x-2)
=(x^2-4)/(x-2)
=(x+2)(x-2)/(x-2)
=x+2

计算[(x-1)/(x-2)-(x-2)(x-3)-(x-3)/(x-4)+(x-4)(x-5)]/(2x-7) 谁会解这道题：(X-5)/(X-7)+(X-2)/(X-4)=(X-3)/(X-5)+(X-4)/(X-6)求X的值 已知x+1/x =4,则x^2/x^4+x^2+1 (x-4)(x-2)-(x-1)(x+3),其中x=-2/5 (4/x-2)+(x+2/2-x)=? x^2/x-2+4/2-x =？ 用两种方法计算：（x/x-2-x/x+2)÷4x/2-x 已知X/(X^2-X+1)=7,求X^2/(X^4+X^2+1)的值 求和：1/[(x+1)(x+2)]+1/[(x+2)(x+3)]+1/[(x+3)(x+4)]+1/[(x+4)(x+5)] 方程(x+1/x+2)+(x+2/x+3)=(x+3/x+4)+(x+4/x+5)的解