高考问答《全职修神》txt全集:初一数学(因式分解)
来源：百度文库 编辑：高考问答 时间：2024/04/29 06:20:19
因式分解:
1.a^2(b-c)+b^2(c-a)+c^2(a-b)
2.x^5n+x^n+1
3.x^5+x+1
1.a^2(b-c)+b^2(c-a)+c^2(a-b)
2.x^5n+x^n+1
3.x^5+x+1
a^2(b-c)+b^2(c-a)+c^2(a-b)
=ba^2-ca^2+cb^2-ab^2+c^2(a-b)
=ba^2-ab^2-ca^2+cb^2+c^2(a-b)
=ab(a-b)-c(a^2-b^2)+c^2(a-b)
=ab(a-b)-c(a+b)(a-b)+c^2(a-b)
=(a-b)[ab-c(a+b)+c^2]
=(a-b)(ab-ac-bc+c^2)
=(a-b)[a(b-c)-c(b-c)]
=(a-b)(a-c)(b-c)
x^5n+x^n+1
=x^5n+x^4n+x^3n-x^4n-x^3n-x^2n+x^2n+x^n+1
=x^3n(x^2n+x^n+1)-x^2n(x^2n+x^n+1)+(x^2n+x^n+1)
=(x^2n+x^n+1)(x^3n-x^2n+1)
x^5+x+1
=x^5+x^4+x^3-x^4-x^3-x^2+x^2+x+1
=x^3(x^2+x+1)-x^2(x^2+x+1)+(x^2+x+1)
=(x^2+x+1)(x^3-x^2+1)