以m开头的小女生英文名:么在WINDOWS环境下远程溢出LIUNX系统啊,LIUNX系统下的服务器漏洞已知情况下 能否给个代码啊

来源:百度文库 编辑:高考问答 时间:2024/04/28 23:54:31
看网上的都是LIUNX对LIUNX的溢出源代码 有没有WINDOWS下的那
LIUNX服务端代码例如:
#include <stdio.h>
#include <netdb.h>
#include <netinet/in.h>

#define BUFFER_SIZE 1024
#define NAME_SIZE 2048

int handling(int c)
{
char buffer[BUFFER_SIZE], name[NAME_SIZE];
int bytes;
strcpy(buffer, "My name is: ");
bytes = send(c, buffer, strlen(buffer), 0);
if (bytes == -1)
return -1;
bytes = recv(c, name, sizeof(name), 0);
if (bytes == -1)
return -1;
name[bytes - 1] = ’\0’;
sprintf(buffer, "Hello %s, nice to meet you!\r\n", name);
bytes = send(c, buffer, strlen(buffer), 0);
if (bytes == -1)
return -1;
return 0;

}

int main(int argc, char *argv[])

{
int s, c, cli_size;
struct sockaddr_in srv, cli;
if (argc != 2)
{
fprintf(stderr, "usage: %s port\n", argv[0]);
return 1;
}
s = socket(AF_INET, SOCK_STREAM, 0);
if (s == -1)
{
perror("socket() failed");
return 2;
}
srv.sin_addr.s_addr = INADDR_ANY;
srv.sin_port = htons( (unsigned short int) atol(argv[1]));
srv.sin_family = AF_INET;
if (bind(s, &srv, sizeof(srv)) == -1)
{
perror("bind() failed");
return 3;
}
if (listen(s, 3) == -1)
{
perror("listen() failed");
return 4;
}
for(;;)
{
c = accept(s, &cli, &cli_size);
if (c == -1)
{
perror("accept() failed");
return 5;
}
printf("client from %s", inet_ntoa(cli.sin_addr));
if (handling(c) == -1)
fprintf(stderr, "%s: handling() failed", argv[0]);
close(c);
}
return 0;
}

已经不可能删掉中文的系统了.只有重新格式化重装了.