gta6的游戏解说视频:(1-1/2)*(1+1/2)*(1-1/3)*(1+1/3)*……*(1-1/99)*(1+1/99)。
来源:百度文库 编辑:高考问答 时间:2024/04/29 00:51:42
(1-1/2)*(1+1/2)*(1-1/3)*(1+1/3)*……*(1-1/99)*(1+1/99)
=(1/2)*(3/2)*(2/3)*(4/3)*(3/4)*……*(98/99)*(100/99)
=(1/2)*(100/99)
=50/99
(1 - 1/2)*(1 + 1/2) = (1*3)/(2*2)
(1 - 1/3)*(1 + 1/3) = (2*4)/(3*3)
(1 - 1/4)*(1 + 1/4) = (3*5)/(4*4)
(1 - 1/5)*(1 + 1/5) = (4*6)/(5*5)
..................................
(1 - 1/98)*(1 + 1/98) = (97*99)/(98*98)
(1 - 1/99)*(1 + 1/99) = (98*100)/(99*99)
原式 = (98! * 100! / 2)/(99!)^2 = 1/99*100/2 = 50/99
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哇!原来不分解啊,哈哈哈,一楼绝妙!
经典的问题
规律的解答
50/99
(1/2005-1)(1/2004-1)........(1/3-1)(1/2-1)
1+1/1+2/=??
1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100)
1+1/1+2+1/1+2+3+......+1/1+2+3+......+10
1/1+1/2+1/3+1/4+。。。。+1/N 是多少
(1-1/2^2)(1-1/3^2)....(1-1/10^2)
(1-1/2^2)(1-1/3^2)....(1-1/10^2)
s=1/1+1/1!+1/2!+1/3!+1/4!+....+1/25!
(1-1/2)*(1+1/2)*(1-1/3)*(1+1/3)*……*(1-1/99)*(1+1/99)。
(1+1/2)*(1-1/2)(1+1/3)*(1-1/3)*.......(1+1/99))*(1-1/99)怎么做