清明上河园儿童门票:分解因式:(X+1)(X+3)(X+5)(X+7)+15

来源:百度文库 编辑:高考问答 时间:2024/05/05 00:48:39

(x+1)(x+3)(X+5)(X+7)+15
=[(x+1)(x+7)]*[(x+3)(x+5)]+15
=(x^2+8x+7)(x^2+8x+15)+15
=(x^2+8x)^2+22(x^2+8x)+105+15
=(x^2+8x)^2+22(x^2+8x)+120
=(x^2+2x+10)(x^2+2x+12)

(x+1)(x+3)(X+5)(X+7)+15
=[(x+1)(x+7)]*[(x+3)(x+5)]+15
=(x^2+8x+7)(x^2+8x+15)+15
=(x^2+8x)^2+22(x^2+8x)+105+15
=(x^2+8x)^2+22(x^2+8x)+120
=(x^2+2x+10)(x^2+2x+12)

(x+1)(x+3)(X+5)(X+7)+15
=[(x+1)(x+7)]*[(x+3)(x+5)]+15
=(x^2+8x+7)(x^2+8x+15)+15
=(x^2+8x)^2+22(x^2+8x)+105+15
=(x^2+8x)^2+22(x^2+8x)+120
=(x^2+2x+10)(x^2+2x+12)

(X+1)(X+3)(X+5)(X+7)+15
=(X^2+8X+7)(X^2+8X+15)+15
=(X^2+8X)^2+22(X^2+8X)+120
=(X^2+8X+10)(X^2+8X+12)
=(X+4+√6)(X+4-√6)(X+2)(X+6)

(x+6)(x^3+10x^2+26x+20)