五金仓库进出明细表:紧急求助一道数学题!!!
来源:百度文库 编辑:高考问答 时间:2024/05/09 19:49:21
约分:(4y^2-x^2)/(x^2-xy-2y^2)
我需要详细的解答过程!!!
谢谢!!!
我需要详细的解答过程!!!
谢谢!!!
=(2y+x)(2y-x)/[(x-2y)(x+y)]
=-(x+2y)/(x+y)
原式=(2y-x)(2y+x)/(x-2y)(x+y)
=(2y+x)/(y-x)
=(2y+x)(2y-x)/[(x-2y)(x+y)]
=-(x+2y)/(x+y)
原式=(2y-x)(2y+x)/(x-2y)(x+y)
=(2y+x)/(y-x)